Question

How many grams of I2 (iodine) are produced by the reaction of 0.360 mol of
CuCl2 according to the following equation?
2 CuCl2 + 4 KI => 2 Cul + 4 KI +I2

45.7
58.6
22.8
91.4

Answer 1

Answer:

A. 45.7

Explanation:

2 CuCl₂ + 4 KI => 2 Cul + 4 KI +I₂

2 mol of CuCl₂ for every 1 mol of I₂ (look at coefficients in balanced equation)

0.360 mol CuCl₂ * 1 mol I₂ / 2 mol CuCl₂ = 0.180 mol I₂

molar mass of I₂ = 2(126.904) = 253.808 g/mol I₂

0.180 mol I₂ * 253.808 g I₂/mol I₂  = 45.685 g I₂