Question

Find the area of △ABC with side lengths b = 9 and c = 14, and included angle A = 145∘. Round your answer to the nearest tenth. Can someone help me please

Answer 1

Answer:

area ≈ 36.1 units²

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = $\frac{1}{2}$ bc sinA , substitute values

  = 0.5 × 9 × 14 × sin145° ≈ 36.1 ( to the nearest tenth )