Answer:
The equation of the given line in point slope form is:
[tex]\:y-1=2\left(x+2\right)[/tex]
Therefore, option A is true.
Step-by-step explanation:
From the diagram
[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(-2,\:1\right),\:\left(x_2,\:y_2\right)=\left(-1,\:3\right)[/tex]
[tex]m=\frac{3-1}{-1-\left(-2\right)}[/tex]
[tex]m=2[/tex]
As point slope form is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
Putting [tex]m=2[/tex] and a point (-2, 1) in the point slope form
[tex]y-1=2\left(x-\left(-2\right)\right)[/tex]
[tex]\:y-1=2\left(x+2\right)[/tex]
Hence, the equation of the given line in point slope form is:
[tex]\:y-1=2\left(x+2\right)[/tex]
Therefore, option A is true.