Answer:
Explanation:
10)
Given data:
Mass of iron = 5 g
Mass of FeO = ?
Solution:
Chemical equation:
2Fe + O₂ → 2FeO
Number of moles of iorn:
Number of moles = mass/ molar mass
Number of moles = 5g / 55.845 g/mol
Number of moles = 0.09 mol
Now we will compare the moles of FeO with Fe.
Fe : FeO
2 : 2
0.09 : 0.09
Theoretical yield of FeO:
Mass of FeO:
Mass = number of moles × molar mass
Mass = 0.09 mol × 71.844 g/mol
Mass = 6.47 g
11)
Given data:
Mass of iron = 5 g
Mass of Fe₂O₃ = ?
Solution:
Chemical equation:
4Fe + 2O₂ → 2Fe₂O₃
Number of moles of iron:
Number of moles = mass/ molar mass
Number of moles = 5g / 55.845 g/mol
Number of moles = 0.09 mol
Now we will compare the moles of FeO with Fe.
Fe : Fe₂O₃
4 : 2
0.09 : 2/4×0.09 = 0.045
Theoretical yield of Fe₂O₃:
Mass of Fe₂O₃:
Mass = number of moles × molar mass
Mass = 0.045 mol × 159.69 g/mol
Mass = 7.2 g
