Question

If n and pare positive integers and 4n/P = V1024, then
the product of n and p is:
(A) -1
(B) 20
(C) 24
(D) 28
(E) 32

Answer 1

Product of n and p is 32 out of available options ! correct option is (E) 32

Step-by-step explanation:

Here we have , n and pare positive integers and 4n/P = V1024, then we need to find the product of n and p . Let's find out:

According to question we have following equation

⇒ $\frac{4n}{p} = \sqrt{1024}$

⇒ $\frac{4n}{p} = \sqrt{32(32)$

⇒ $\frac{4n}{p} = \sqrt{32^2$

⇒ $\frac{4n}{p} = 32$

⇒ $n=8p$

Now , product of n and p is :

⇒ $np$

⇒ $(8p)p$

⇒ $8p^2$

Value of p is positive integer So , Let f(p)=  $8p^2$ :

$f(1)=8(1)^2=8\\f(2)=8(2)^2=32\\f(3)=8(2)^3=64$

Hence , Product of n and p is 32 out of available options ! correct option is (E) 32 .