f(3) = 69
Step-by-step explanation:
Given f(x) =5x5 + 10x4 + 3x3 + 8x2 – 6x – 3; c = 3
f(x) = 25+40+9+16 - 6x - 3
f(x) = - 6x +90-3
f(x) = - 6f(3) = 69x + 87
Taken c = 3
f(c) = - 6c +90-3
f(c) = - 6c + 87
substitute c=3
f(3) = - 6 (3) +90-3
= -18 +87
= 69
Hence .,f(3) = 69
