The expression [tex]$\frac{3}{(x+6)}[/tex] is equal to the rational expression when x does not equal -2 or -6.
How to find the rational expression when x does not equal -2 or -6?
The given expression exists
[tex]$f(x)=\frac{3(x+2)}{(x+6)(x+2)}$[/tex]
We have x + 2 common in numerator and denominator, there exists a hole at x + 2 = 0, that exists at x = -2.
And a function exists undefined when the denominator exists at zero.
And at x = -6, the denominator becomes zero.
So, at x = -6, the function exists undefined, or there exists a vertical asymptote at x = -6 and hole at x = -2.
The expression [tex]$\frac{3}{(x+6)}[/tex] exists equivalent to the rational expression when x does not equal -2 or -6.
Therefore, the correct answer is option B. [tex]$\frac{3}{(x+6)}[/tex].
To learn more about rational expression
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