Question

3. Two charged boxes are 4 meters apart from each other. The blue box has a charge of +0.000337
C and is attracting the red box with a force of 626 Newtons. Determine charge of the red box.
Remember to indicate if it is positive or negative.
0.0033 C

Answer 1

Answer:

Charge on the red box is -0.0033 C as it is attracting the blue box

Explanation:

As we know that two boxes are attracting each other

So here we can say that two boxes will have opposite charges

So as we know that electrostatic force between two charges is given as

$F = \frac{kq_1q_2}{r^2}$

here we have

here we know that

$k = 9 \times 10^9$

$q_1 = 0.000337 C$

r = 4 m

F = 626 N

$626 = \frac{(9\times 10^9)(0.000337)q}{4^2}$

$q = 0.0033 C$

Answer 2

The charge on the red box is -0.0033 C. It states that the electrostatic force between two charged objects is proportional to the product of the charges

What is Coulomb's Law?

It states that the electrostatic force between two charged objects is proportional to the product of the charges and inversely proportional to the distance between them.

$F = k \frac{q_1q_2}{r^2}$

Where,

$F$ = electric force = 626 N

$k$ = Coulomb constant = $8.99 \times 10^9 {\rm Nm^2 /C^2}$

$q_1$ = Charge on the blue box =  +0.000337 C

$q_2$     =      Charge on the red object = ?

$r$ = distance of separation = 4 m

Now put the values in the formula,

$626 = 8.99 \times 10^9\times \dfrac{+0.000337 C\times q_2}{4^2}\\\\q_2 = -0.0033 \rm \ C$

Therefore, the charge on the red box is -0.0033 C.

Learn more about Coulomb's Law:

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