Question

A box contains 6 red marbles and 4 white marbles. one marble is pulled from the box and not replaced. then a second marble is pulled from the box. what is the probability both marbles are white?

Answer 1

Answer:

2/15

Step-by-step explanation:

There are 10 marbles in the box

P (1st marble white) = white/total

                                 =4/10= 2/5

We keep the marble

There are now 9 marbles in the box, 6 red and 3 white

P (2nd marble white no replace) = white /total

                                   = 3/9 = 1/3

P(white, white no replacement) = P (1stwhite) P(2nd white no replace)

                                                     = 2/5 *1/3

                                                     = 2/15