Answer:
[tex]P(t)=43.2(1.06)^t[/tex]
Step-by-step explanation:
We have been given that searches related in 1997 there were 43.2 who used free weights increases 6% annually. We are asked to write an equation for the number of people using free weights t year after 1997.
Let [tex]t=0[/tex] represent year 1997.
We will use exponential growth formula to write our given function.
[tex]y=a\cdot (1+r)^x[/tex], where,
y = Final value,
a = Initial value,
r = Growth rate in decimal form,
x = time.
Let us convert 6% into decimal form.
[tex]6\%=\frac{6}{100}=0.06[/tex]
Initially there were 43.2 who used free weights, so initial value is 43.2.
Upon substituting our given values in exponential growth formula, we will get:
[tex]P(t)=43.2(1+0.06)^t[/tex]
[tex]P(t)=43.2(1.06)^t[/tex]
Therefore, our required equation would be [tex]P(t)=43.2(1.06)^t[/tex].