Question

At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded per student:203,245,237,233,90,100,100,277,265,264,265,285,288,291,
291,290,300,224,200,257,290,279,266,288
what is the mean of the number of jumps

Answer 1

the mean of the number of jumps is 243 .

Step-by-step explanation:

Here we have , At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded per student:203,245,237,233,90,100,100,277,265,264,265,285,288,291, 291,290,300,224,200,257,290,279,266,288  . We need to find mean of the number of jumps . Let's find out:

We know that   $Mean = \frac{x_1+x_2+.......+x_n}{n}$   where $x_1,x_2,........,x_n$ are the data and n is the number of data we have ! Now , according to question :

⇒ Mean = ( 203+245+237+233+90+100+100+277+265+264+265+285+288+291+

291+290+300+224+200+257+290+279+266+288 ) / ( 24 )

⇒ $Mean= \frac{5828}{24}$

⇒ $Mean= 243$

Therefore , the mean of the number of jumps is 243 .