Question

Find the class interval that contains the median

Answer 1

Answer:

2≤h≤3

Step-by-step explanation:

The frequencies are 4 , 8, 11, and 7.

The total frequency is

$4 + 8 + 11 + 7 = 30$

The median class is given by :

$\frac{1}{2} \sum f \: \: th- - - occurrence$

Half of 30 is 15.

The median class corresponds to the 15th occurrence.

From the frequency table, we add from top until we get or the least number greater than 15:

4+8+11=23

Meaning the median class is 2≤h≤3

Adding from the bottom of the frequency also points to the same class.

The median class is 2≤h≤3

Answer 2

Class interval refers to the numerical width of any class in a particular distribution.

Class interval $2\leq h<3$ contains the median.

The cumulative frequency is calculated by adding each frequency from a frequency distribution table to the sum of its predecessors.

Now, form table

Number of hours (h)            frequency             cumulative frequency

$0\leq h<1$                                  4                                    4

$1\leq h<2$                                  8                                    12

$2\leq h<3$                                 11                                    23

$3\leq h<4$                                 7                                     30

Total number of frequency , n = 4 + 8 + 11 + 7 = 30

The median is the middle number

  So,  $\frac{n}{2} =\frac{30}{2}=15$

15 is comes under cumulative frequency  23 ,

So, class of interval that contains median is $2\leq h<3$

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