Respuesta :
factor took out was [tex]y^2[/tex] , And resultant expression is [tex]y\sqrt{3}[/tex] .
Step-by-step explanation:
Here we need to Take a factor out of the square root: sqrt(3y^2) , where y<0 .Let's do this :
The given expression is sqrt(3y^2) or , [tex]\sqrt{(3y^2)}[/tex]
We know that , to take out a factor out of the square root that factor must have a degree in multiple of 2 , as [tex]x^2,x^4,x^16,(x+6)^2,(x-2)^4[/tex] etc . So ,
⇒ [tex]\sqrt{3y^2}[/tex]
⇒ [tex]\sqrt{3}(\sqrt{y^2})[/tex]
⇒ [tex]\sqrt{3}(y^2)^{\frac{1}{2}[/tex]
⇒ [tex]\sqrt{3}(y)^{\frac{2}{2}[/tex]
⇒ [tex]y\sqrt{3}[/tex]
Therefore , factor took out was [tex]y^2[/tex] , And resultant expression is [tex]y\sqrt{3}[/tex] .
Answer:
-y × sqrt(3)
Step-by-step explanation:
3y²
3 × (-y)²
sqrt(3 × (-y)²)
-y × sqrt(3)
y < 0
-y > 0