Question

Take a factor out of the square root:
sqrt(3y^2) , where y<0

Answer 1

factor took out was $y^2$ , And resultant expression is  $y\sqrt{3}$ .

Step-by-step explanation:

Here we need to Take a factor out of the square root:  sqrt(3y^2) , where y<0 .Let's do this :

The given expression is  sqrt(3y^2) or , $\sqrt{(3y^2)}$

We know that , to take out a factor out of the square root that factor must have a degree in multiple of 2 , as   $x^2,x^4,x^16,(x+6)^2,(x-2)^4$  etc . So ,

⇒ $\sqrt{3y^2}$

⇒ $\sqrt{3}(\sqrt{y^2})$

⇒ $\sqrt{3}(y^2)^{\frac{1}{2}$

⇒ $\sqrt{3}(y)^{\frac{2}{2}$

⇒ $y\sqrt{3}$

Therefore , factor took out was $y^2$ , And resultant expression is  $y\sqrt{3}$ .

Answer 2

Answer:

-y × sqrt(3)

Step-by-step explanation:

3y²

3 × (-y)²

sqrt(3 × (-y)²)

-y × sqrt(3)

y < 0

-y > 0