Question

write the factored form of y2 + 11y + 28.

Answer 1

Answer:

$\mathrm{Factor}\:y^2+11y+28:\quad \left(y+4\right)\left(y+7\right)$

Step-by-step explanation:

Given the expression

$y^2+11y+28$

The expression can be written as into groups such as:

$=\left(y^2+4y\right)+\left(7y+28\right)$

$\mathrm{Factor\:out\:}y\mathrm{\:from\:}y^2+4y\mathrm{:\quad }y\left(y+4\right)$

$\mathrm{Factor\:out\:}7\mathrm{\:from\:}7y+28\mathrm{:\quad }7\left(y+4\right)$

so

$=y\left(y+4\right)+7\left(y+4\right)$

$\mathrm{Factor\:out\:common\:term\:}y+4$

$=\left(y+4\right)\left(y+7\right)$

Therefore,

$\mathrm{Factor}\:y^2+11y+28:\quad \left(y+4\right)\left(y+7\right)$