A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water to the shark is 19 degrees, what is the horizontal distance between the boat and the shark? Round your answer to the nearest foot.

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Answer:

The answer to your question is the horizontal distance = 81.32 ft

Step-by-step explanation:

Data

depth = 28 ft

angle = 19°

horizontal = ?

To solve this problem, use trigonometric functions. The trigonometric function that relates the opposite side and the adjacent side is the tangent.

       tan Ф = Opposite side/Adjacent side

-Solve for adjacent side

       Adjacent side = Opposite side / tanФ

-Substitution

       Adjacent side = 28 / tan 19

-Simplification

       Adjacent side = 28 / 0.3443

-Result

       Adjacent side = 81.32 ft

The horizontal distance between the boat and the shark is 82.35 feet.

Given that,

A shark is swimming 28 feet below sea level.

If the angle of depression from a boat on the water to the shark is 19 degrees,

We have to determine,

What is the horizontal distance between the boat and the shark?

According to the question,

A shark is swimming 28 feet below sea level.

If the angle of depression from a boat on the water to the shark is 19 degrees,

The angle of depression is the angle between the horizontal line from the observation point which is equal to,

[tex]\rm Tan\theta = \dfrac{Perpendicular}{Horizontal \ line}[/tex]

Substitute all the values in the formula;

[tex]\rm \rm Tan\theta = \dfrac{Perpendicular}{Horizontal \ line}\\\\Tan19 = \dfrac{28}{Horizontal \ line}\\\\Horizontal \ line = \dfrac{28}{0.344}\\\\Horizontal \ line = 82.35 \ feet[/tex]

Hence, The required horizontal distance between the boat and the shark is 82.35 feet.

For more details refer to the link given below.

https://brainly.com/question/640166

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