Answer:
x² + 3x – 1=0
Step-by-step explanation:
hello :
calculate : ∆ = b² - 4ac
x² + x + 3 = 0 : a =1 b=1 c=3 ∆ = (1)² - 4(1)(3)= -11 < 0 non reals roots
x² + 2x - 8=0 : a =1 b=2 c=-8 ∆ = (2)² - 4(1)(-8)=36 two rational roots
x² + 3x – 1=0 : a =1 b=3 c=-1 ∆ = (3)² - 4(1)(-1) = 13 no perfect squard
so : two irrational roots?
x2 - 2x + 1 = 0 : (x-1)²=0 one root