Question

Which quadratic equation has two irrational roots?
O x2 + x + 3 = 0
O x² + 2x - 8=0
x² + 3x – 1=0
x2 - 2x + 1 = 0

Answer 1

Answer:

x² + 3x – 1=0

Step-by-step explanation:

hello :

calculate : ∆ = b² - 4ac

x² + x + 3 = 0  :  a =1     b=1     c=3      ∆ = (1)² - 4(1)(3)= -11 < 0 non reals roots

x² + 2x - 8=0  :  a =1     b=2     c=-8     ∆ = (2)² - 4(1)(-8)=36 two rational roots

x² + 3x – 1=0  :  a =1     b=3     c=-1      ∆ = (3)² - 4(1)(-1) = 13 no perfect squard

so : two irrational roots?

x2 - 2x + 1 = 0 : (x-1)²=0      one root