Answer:
1. 4Na + O2 —> 2Na2O
2. 15.5g
Explanation:
1. The reaction between sodium (Na) and oxygen gas (O2) produced sodium oxide (Na2O). This is illustrated below:
Na + O2 —> Na2O
The equation can be balance as follows:
There are 2 atoms of O on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of Na2O as shown below:
Na + O2 —> 2Na2O
Now, we have 4 atoms of Na on the right side and 1atom on the left side. It can be balance by putting 4 in front of Na as shown below:
4Na + O2 —> 2Na2O
Now the equation is balanced.
2. To obtain the mass of the product formed from 11.5g of sodium (Na), first, let us obtain the masses formed from the balanced equation. This is illustrated below:
4Na + O2 —> 2Na2O
Molar Mass of Na = 23g/mol
Mass of Na from the balanced equation = 4 x 23 = 92g
Molar Mass of of Na2O = (23x2) + 16 = 46 + 16 = 62g/mol
Mass of Na2O from the balanced equation = 2 x 62 = 124g
From the balanced equation,
92g of Na produced 124g of Na2O.
Therefore, 11.5g of Na will produce = (11.5 x 124)/92 = 15.5g of Na2O
Therefore, 15.5g of the product (Na2O) are produced
