Question

A bar of soap (mass 0.1 kg) is sliding at 1.5 m/s, before smashing into a motionless bar of soap (mass 0.08 kg). After hitting each other, the soap sticks together and continues to slid. Ignore friction. what is the velocity of bars of soap after sticking together?

Answer 1

Answer:

5/6 = 0.833

Explanation:

From conservation of momentum,

m1*u1  + m2*u2 =  (m1+m2)*v

v = (m1*u1 + m2*u2)/(m1*m2)

Putting in the values, we get, v = 5/6 = 0.833