A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.

At this time, the rocket runs out of fuel and turns off, and the car deploys a parachute to slow down, and the parachute performs 36,733 J of work on the car.

What is the final speed of the car after this work is performed?



Respuesta :

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

[tex]W=K_f -K_i[/tex]

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

[tex]K_i = 66,120 J[/tex] is the initial kinetic energy of the car

[tex]K_f[/tex] is the final kinetic energy

Solving,

[tex]K_f = K_i + W=66,120+(-36,733)=29387 J[/tex]

The final kinetic energy of the car can be written as

[tex]K_f = \frac{1}{2}mv^2[/tex]

where

m = 661 kg is its mass

v is its final speed

Solving for v,

[tex]v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s[/tex]

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