Question

2
A tether ball tied to a pole by a rope swings in a circular path with a centripetal
acceleration of 2.7 m/s2. If the ball has a tangential speed of 2.0 m/s, what is the
diameter of the circular path in which it travels?
A 0.74 m
B 1.5 m
C 3.0 m
D 3.6 m

Answer 1

Answer:

Diameter of the circle is 3.0 m

Explanation:

As we know that the centripetal acceleration of the object moving in circular path is given as

$a_c = \frac{v^2}{R}$

so we have

$a_c = 2.7 m/s^2$

$v = 2 m/s$

now we have

$2.7 = \frac{2^2}{R}$

$R = 1.5 m$

So diameter of the circle is

d = 2R = 3.0 m