Answer:
no
Step-by-step explanation:
The sequence can be described by an exponential function with a base of 1.
a(n) = 1^n
This is what might be called a "degenerate" case. The function neither grows nor decays. While the terms do not diverge, their sum does.
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Additional comment
It can also be described as an arithmetic sequence with a common difference of zero.
a(n) = 1 + 0·n
