Question

The parallax of heavenly body measured from two points diametrically opposite on the equator of the earth is 1.0 min. If the radius is 6400km of the earth , find the distance of the heavenly body from the center of the earth in AV. Take 1AV=1.5×10^2

Answer 1

Answer:

e = 1 min = 1\60 ×  $\pi/180$rad

r=1/0

l = 2×6400×$10x^{3}$×60×180

Explanation: