Question

For what value of a does the equation ax2−3x−5=0 have 1 as one of its roots?

Answer 1

Answer:

a=8

Step-by-step explanation:

If we plug the equation into the quadratic formula we get:

$\frac{3+\sqrt{9+20a}}{2a}$ and $\frac{3-\sqrt{9+20a}}{2a}$ so then we can do $\frac{3+\sqrt{9+20a}}{2a}$ = 1

After doing that work out we find that a = 8.

I mean its not like you need the paper homework since there are online now classes yknow so...