Respuesta :
Answer:
Explanation:
Heat generated = I² Rt , I is current , R is resistance , t is time .
= 1.5 x 1.5 x 10 x 150
Q = 3375 J
Q = m s ΔT , m is mass , s is specific heat of water , ΔT is rise in temperature.
ΔT = Q / m s
= 3375 / 57.5 x 4.2
= 14 k
Final temperature
= 298 + 14
= 312 k
Answer:
Final temperature =311.97 K
Explanation
Let us first calculate the energy released when current is passed
by using the formula
[tex]E=I^2Rt[/tex]
where I =1.50 A , R = 10.0 Ω , t = 150 s
Now lets put these values in the above equation to get
[tex]E=1.5^2\times10\times150[/tex]
=3375 J
To calculate the change in temperature
Heat released( q ) = m× s × Δ T
m= mass of liquid =57.5 g, s= specific heat capacity of water = 4.2 J/g K
ΔT= difference in temperature =(T-298) K, considering T to be the final temperature.
therefore,
3375=57.5×4.2×(T-298)
⇒T= (3375+57.5×4.2×298)/57.5×4.2
T=311.97 K