Answer:
[tex]\frac{3+i}{-2i}[/tex] = -0.5 + 1.5i
Step-by-step explanation:
Given 3+i divided by -2i ⇒ [tex]\frac{3+i}{-2i}[/tex]
By multiplying the numerator and the denominator by the conjugate of (-2i) which will be equal (2i)
So, [tex]\frac{3+i}{-2i}[/tex] = [tex]\frac{3+i}{-2i} *\frac{2i}{2i} = \frac{i(3+i)}{-2i^2} = \frac{i^2+3i}{-2i^2}[/tex]
We should know that: i = √(-1) ⇒ i² = -1
∴ [tex]\frac{i^2+3i}{-2i^2} = \frac{-1+3i}{-2*-1} = \frac{-1+3i}{2} = -0.5 + 1.5i[/tex]
∴ [tex]\frac{3+i}{-2i}[/tex] = -0.5 + 1.5i
