Answer: 29.0 years
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{12.5years}=0.0554years^{-1}[/tex]
b) for decomposition of 80 % of reactant
[tex]t=\frac{2.303}{0.0554}\log\frac{100}{100-80}[/tex]
[tex]t=\frac{2.303}{0.0554}\log\frac{100}{20}[/tex]
[tex]t=29.0 years[/tex]
The age of a suspected vintage wine that is 20 % as radioactive as a freshlybottled specimen is 29.0 years