A farmer has three silos. The largest silo has a diameter of 24 feet. The radius of the smallest silo is one-thrid as big as the diameter of the largest. The middle sized silo has a radius that is 2 feet greater than the radius of the smallest silo. What is the circumference of each silo?

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Answer:

Exact:

[tex] 16 \pi~ft;~~20 \pi~ft;~~24 \pi~ft [/tex]

Approximate:

50.3 ft, 62.8 ft, 75.4 ft

Step-by-step explanation:

Let's find the radius of each silo using the given information.

"The largest silo has a diameter of 24 feet."

[tex] d_{largest} = 24~ft [/tex]

[tex] r_{largest} = \dfrac{d_{largest}}{2} = \dfrac{24~ft}{2} = 12~ft [/tex]

"The radius of the smallest silo is one-third as big as the diameter of the largest."

[tex] r_{smallest} = \dfrac{24~ft}{3} = 8~ft [/tex]

"The middle-sized silo has a radius that is 2 feet greater than the radius of the smallest silo."

[tex] r_{middle} = r_{smallest} + 2~ft = 8~ft + 2~ft = 10~ft [/tex]

The three radii are: 8 ft, 10 ft, and 12 ft.

Now we use the circumference formula with each radius to find the circumferences.

Smallest:

[tex] C = 2 \pi r = 2 \times \pi \times 8~ft = 16 \pi~ft [/tex]

Middle:

[tex] C = 2 \pi r = 2 \times \pi \times 10~ft = 20 \pi~ft [/tex]

Largest:

[tex] C = 2 \pi r = 2 \times \pi \times 12~ft = 24 \pi~ft [/tex]

The circumferences above are exact. If you want approximations, then use a calculator and an approximation for pi.

The circumferences are approximately: 50.3 ft, 62.8 ft, 75.4 ft

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