An arithmetic sequence has a1 = 4 and d= 3

Answer:
Step-by-step explanation:
hello :
a1 = 4 and d= 3
a2 = a1+d = 4+3=7
a3 =a2+d =7+3=10
a4=a3+d =10+3 = 13
a5 =a4+d = 13+3 =16
Solutions:
a1 = 4 and d= 3
a2 = a1+d = 4+3=7
a3 =a2+d =7+3=10
a4=a3+d =10+3 = 13
a5 =a4+d = 13+3 =16