Answer:
Below in bold.
Explanation:
1 mole of an element contains 6.022* 10^23 atoms.
Ethanol has the molecular formula C2H5OH.
So we have 2 carbon atoms, 6 hydrogen atoms ans 1 oxygen atom in the molecule.
Using molar masses the mass of carbon in 36.7 g of C2H5OH
= [(2 * 12.011) / (2*12.011 + 6*1.008 + 15.999)] * 36.7
= [(2 * 12.011) /46.069] * 36.7
= 19.14 g
So the number of carbon atoms = (19.14 / 12.011) * 6.022* 10^23
= 9.596 * 10^23. (Answer).
Using molar masses the mass of hydrogen in 36.7 g of C2H5OH
= [(6 * 1.008) / (46.069)] * 36.7
= 4.818 g
So the number of hydrogen atoms = (4.818 / 1.008) * 6.022* 10^23
= 2.878 * 10^24 (Answer).
Using molar masses the mass of oxygen in 36.7 g of C2H5OH
= [(15.999) / (46.069)] * 36.7
= 12.745 g
So the number of hydrogen atoms = (12.745 / 15.999) * 6.022* 10^23
= 2.924 * 10^24 (Answer).
Answer:
C atoms = 9.6 *10^23 atoms
H atoms = 2.9*10^24 atoms
O atoms = 4.8 *10^23 atoms
Explanation:
Step 1: Data given
Mass of ethanol = 36.7 grams
Molar mass of ethanol = 46.07 g/mol
Step 2: Calculate moles of ethanol
Moles ethanol = mass / molar mass
Moles ethanol = 36.7 grams / 46.07 g/mol
Moles ethanol = 0.797 moles
Step 3: Calculate moles
For 1 mol C2H5OH we have 2 moles C, 6 moles H and 1 mol O
For 0.797 moles C2H5OH we have:
2*0.797 = 1.594 moles C
6*0.797 = 4.782 moles H
1*0.797 = 0.797 moles O
Step 4: Calculate carbon atoms
C atoms = moles C * number of Avogadro
C atoms = 1.594 moles * 6.02 *10^23
C atoms = 9.6 *10^23 atoms
Step 5: Calculate H atoms
H atoms = 4.782 moles * 6.02 * 10^23
H atoms = 2.9*10^24 atoms
Step 6: Calculate O atoms
O atoms = 0.797 moles * 6.02 *10^23
O atoms = 4.8 *10^23 atoms
