Question

a.) If log(2x + 3) -log(x - 1) = 3, then the equation in exponential form is 10^3= (2x + 3)(x - 1).
Is this true or false? If false how do I fix it

Answer 1

Step-by-step explanation:

One of the logarithm rules states the following:

$log{a} - log{b} = log{\frac{a}{b}}$

For this problem, that means the following:

$log{2x + 3} - log{x - 1} = log{\frac{2x + 3}{x - 1}}$

So now we have the following:

$log{\frac{2x + 3}{x - 1}} = 3$

Rolling the log, we get the following:

$10^{3} = \frac{2x + 3}{x - 1}$