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Answer:
2H₂O₂ → 2H₂O + O₂
24.7 L are the liters of formed oxygen.
Explanation:
We state the reaction:
2H₂O₂ → 2H₂O + O₂
2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.
We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles
As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles
We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g
Let's use oxygen's density to find out the volume
δ O₂ = 1.429 g/L (mass/volume)
35.3 g . 1L / 1.429g = 24.7 L
Answer:
24.64 L of O2 will be produced
Explanation:
Step 1: Data given
Mass of hydrogen peroxide = 75.0 grams
Molar mass of hydrogen peroxide (H2O2) = 34.015 g/mol
Step 2: The balanced equation
2H2O2 → 2H2O + O2
Step 3: Calculate moles H2O2
Moles H2O2 = 75.0 grams / 34.015 g/mol
Moles H2O2 = 2.20 moles
Step 4: Calculate moles O2
For 2 moles H2O2 we'll have 2 moles H2O and 1 mol O2
For 2.20 moles H2O2 we'll have 2.20/2 = 1.10 moles O2
Step 5: Calculate volume of O2
For 1 mol we have 22.4 L
For 1.10 moles we have 1.10 * 22.4 L = 24.64 L
24.64 L of O2 will be produced