Answer:
The answer is A
Step-by-step explanation:
B f(n) = 2 * 3^(n-1)
A. f(n) = (n-1)^2 +3
3, 4,7,12,19
2,6,8,54, 162
This is the solution
C f(n) = 2^n +1
3,5,9,17,33
D f(n) = 3n
3,6,9,12,15