How much energy is needed to raise the temperature of a 200 g piece of lead by 250 o C?

Answer: The amount of energy required to raise the given amount of temperature is 6400 J
Explanation:
To calculate the heat absorbed by the lead, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed
m = mass of lead = 200 g
c = heat capacity of lead = 0.128 J/g°C
[tex]\Delta T[/tex] = change in temperature = 250°C
Putting values in above equation, we get:
[tex]q=200g\times 0.128J/g^oC\times 250^oC=6400J[/tex]
Hence, the amount of energy required to raise the given amount of temperature is 6400 J