Respuesta :
Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
According to H-W equilibrium theory, in the equation p² + 2pq + q² = 1, 2pq represent the frequency of the heter0zyg0us genotype. Option D).
What is Hardy-Weinberg Equilibrium?
The Hardy-Weinberg equilibrium is a theory that states that allelic and genotypic frequencies remain the same through generations in a population that is in equilibrium.
For a population to be in equilibrium, there must be
- no migration,
- no mutation,
- no natural selection,
- no genetic flow,
- nor genetic drift.
No evolutive force must be acting on these populations. They are not evolving.
Assuming a diallelic gene,
⇒ The allelic frequencies in a locus are represented as p and q.
• The frequency of the dominant allele p(X) is p
• The frequency of the recessive allele p(x) is q
⇒ The genotypic frequencies after one generation are
• p² (H0m0zyg0us dominant genotypic frequency),
• 2pq (Heter0zyg0us genotypic frequency),
• q² (H0m0zyg0us recessive genotypic frequency).
The addition of the allelic frequencies equals 1
p + q = 1.
The sum of genotypic frequencies equals 1
p² + 2pq + q² = 1
According to H-W equilibrium theory, in the equation p² + 2pq + q² = 1, 2pq represent the frequency of the heter0zyg0us genotype. Option D).
A) The frequency of the h0m0zyg0us recessive genotype ⇒ q²
B) The frequency of all the genotypes ⇒ p², 2pq, q²
C) The frequency of the h0m0zyg0us dominant genotype ⇒ p²
D) The frequency of the heter0zyg0us genotype ⇒ 2pq
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