Question

A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Round your answer to the nearest whole number. (1 ft3 ≈ 7.5 gal)

Answer 1

The cylindrical swimming pool contain 4512 gallons of water, if a pool diameter has a diameter of 16 feet and a height of 3 feet.

Step-by-step explanation:

       The given is,

                Diameter of swimming pool is 16 feet

                Height of swimming pool is 3 feet

Step:1

        Formula for volume of cylinder is,

                            $Volume, V=\pi r^{2} h$........................(1)

       Where, r - Radius

                    h - Height

       Formula for radius,

                                          $r=\frac{d}{2}$

                                             = $\frac{16}{2}$

                                          r = 8 feet

Step:2

         From equation (1)

                                        $= \pi (8^{2} )(3)$

                                         $= \pi (64)(3)$

                                         $= \pi (192)$

                                     V  $= 603.185$ cubic feet

Step:3

          From given ( 1 cubic feet = 7.5 gallons )

                                    $V = (603.185)(7.5)$

                                        $= 4523.88$

                                    V ≅ 4524 gallons

Result:

          The cylindrical swimming pool contain 4512 gallons of water, if a pool diameter has a diameter of 16 feet and a height of 3 feet.

Answer 2

4512 mark me as brainliest pls!