Question

2) The perimeter of a rectangle is 238 inches. The width is 14 less than 3/4 of the length. Find the area of
the rectangle.

Answer 1

Answer:

$Area=3268inches^2$

Step-by-step explanation:

Perimeter=238 inches

$Width=\frac{3}{4}*Length-14$

$W=\frac{3}{4}*L-14$

Perimeter of a rectangle= 2(Length+Width)

$238=2(L+(\frac{3}{4}L-14) )\\\\238=2(L+(\frac{3L-56}{4} ))\\\\238=2(\frac{4L+(3L-56)}{4} )\\\\238=2(\frac{(7L-56)}{4} )\\\\238=\frac{7L-56}{2} \\\\238*2=7L-56\\\\7L-56=476\\\\7L=476+56\\\\7L=532\\\\L=532/7\\\\L=76 inches$

Width is:

$W=\frac{3}{4}*L-14$

               Width $=(\frac{3}{4}*76)-14 \\\\=(3*19)-14\\\\=57-14\\\\=43inches$

Area of a rectangle:

                       $Length*Width\\\\=76*43\\\\=3268 inches^2$

$Area=3268inches^2$

Answer 2

Answer:

Area=3268inches^2