Question

Calculate the acceleration of a bus whose speed changes from 6 m/s to 12 m/s over a period of 3 s.

Answer 1

Answer:

Answer is: Acceleration=2 m/s^2

Explanation:

Given:

Initial velocity: 6 m/s

final velocity: 12 m/s

Time: 3 s

The formula: final velocity - initial velocity ÷ time

So,

12 m/s - 6 m/s ÷ 3 s

6 m/s ÷ 3 s

= 2 m/s^2

Answer 2

The acceleration of the moving bus with the given initial, final velocity and elapsed time is 2m/s².

What is the acceleration of the bus?

From the First Equation of Motion;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given that;

• Initial velocity u = 6m/s

• Final velocity v = 12m/s

• Elapsed time t = 3s

• Acceleration of the bus a = ?

v = u + at

12m/s = 6m/s + ( a × 3s )

a × 3s = 12m/s - 6m/s

a × 3s = 6m/s

a = 6m/s ÷ 3s

a = 2m/s²

Therefore, the acceleration of the moving bus with the given initial, final velocity and elapsed time is 2m/s².

Learn more about Equations of Motion here: brainly.com/question/18486505

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