At a basketball game, an air cannon launches T-shirts into the crowd. The function y=−1/8x^2 + 4x represents the path of a T-shirt. The function 3y =2x − 14 represents the height of the bleachers. In both functions, y represents vertical height (in feet) and x represents horizontal distance (in feet). At what height does the T-shirt land in the bleachers?

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Answer:

The T-shirt lands in the bleachers at a height of 14 feet.

Step-by-step explanation:

The point where they meet is the solution of the simultaneous system of equations:

[tex]y = -\frac{1}{8}x^2+4x[/tex]...........................................(1)

[tex]3y = 2x - 14[/tex]..............................................(2)

From (2),

[tex]y = \frac{2}{3}x-\frac{14}{3}[/tex].................................................(3)

Substituting (3) in (1),

[tex]\frac{2}{3}x-\frac{14}{3} = -\frac{1}{8}x^2+4x[/tex]

Multiply through by 24 (the LCM of 3 and 8, the denominators of the fractions)

[tex](24\times\frac{2}{3}x)-(24\times\frac{14}{3}) = (-24\times \frac{1}{8}x^2)+(24\times4x)[/tex]

[tex]16x - 112 = -3x^2+96x[/tex]

[tex]3x^2-80x -112 = 0[/tex]

[tex](x-28)(3x+4) = 0[/tex]

[tex]x-28 = 0[/tex]                 OR        [tex]3x+4=0[/tex]

[tex]x=28[/tex]                       OR        [tex]x = -\frac{4}{3}[/tex]

The value of y represents the height.

Substituting for x in (3)

[tex]y = \frac{2}{3}\times28-\frac{14}{3} = \frac{56}{3} - \frac{14}{3} = 14[/tex]

[tex]y = \frac{2}{3}\times(-\frac{4}{3})-\frac{14}{3} = -\frac{8}{9} - \frac{14}{3} = -\frac{50}{9}[/tex]

We discard the negative answer.

Hence, the T-shirt lands in the bleachers at a height of 14 feet.

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