Answer:
The T-shirt lands in the bleachers at a height of 14 feet.
Step-by-step explanation:
The point where they meet is the solution of the simultaneous system of equations:
[tex]y = -\frac{1}{8}x^2+4x[/tex]...........................................(1)
[tex]3y = 2x - 14[/tex]..............................................(2)
From (2),
[tex]y = \frac{2}{3}x-\frac{14}{3}[/tex].................................................(3)
Substituting (3) in (1),
[tex]\frac{2}{3}x-\frac{14}{3} = -\frac{1}{8}x^2+4x[/tex]
Multiply through by 24 (the LCM of 3 and 8, the denominators of the fractions)
[tex](24\times\frac{2}{3}x)-(24\times\frac{14}{3}) = (-24\times \frac{1}{8}x^2)+(24\times4x)[/tex]
[tex]16x - 112 = -3x^2+96x[/tex]
[tex]3x^2-80x -112 = 0[/tex]
[tex](x-28)(3x+4) = 0[/tex]
[tex]x-28 = 0[/tex] OR [tex]3x+4=0[/tex]
[tex]x=28[/tex] OR [tex]x = -\frac{4}{3}[/tex]
The value of y represents the height.
Substituting for x in (3)
[tex]y = \frac{2}{3}\times28-\frac{14}{3} = \frac{56}{3} - \frac{14}{3} = 14[/tex]
[tex]y = \frac{2}{3}\times(-\frac{4}{3})-\frac{14}{3} = -\frac{8}{9} - \frac{14}{3} = -\frac{50}{9}[/tex]
We discard the negative answer.
Hence, the T-shirt lands in the bleachers at a height of 14 feet.