the value of the discriminant of the quadratic equation [tex]-2x^2=-8x+8[/tex] is [tex]D =0[/tex] .
Step-by-step explanation:
Here we need to find What is the value of the discriminant of the quadratic equation -2x^2=-8x+8 or , [tex]-2x^2=-8x+8[/tex] .
We know that for a quadratic equation , [tex]f(x) = ax^2+bx+c[/tex] , Discriminant is :
⇒ [tex]D = b^2-4ac[/tex]
Now , let's frame equation [tex]-2x^2=-8x+8[/tex] in form of [tex]f(x) = ax^2+bx+c[/tex] :
⇒ [tex]-2x^2=-8x+8[/tex]
⇒ [tex]2x^2-8x+8=0[/tex]
⇒ [tex]x^2-4x+4=0[/tex]
Comparing values we get that here , a=1 , b = -4 , c = 4 . Putting these values in [tex]D = b^2-4ac[/tex] :
⇒ [tex]D = (-4)^2-4(1)(4)[/tex]
⇒ [tex]D =16-16[/tex]
⇒ [tex]D =0[/tex]
Therefore , the value of the discriminant of the quadratic equation [tex]-2x^2=-8x+8[/tex] is [tex]D =0[/tex] .
