Respuesta :

[tex]a^2-b^2-4b-4[/tex] in form of multiplication is  [tex](a-b)(a+b)-4(b+1)[/tex] .

Step-by-step explanation:

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , [tex]a^2-b^2-4b-4[/tex] :

⇒  [tex]a^2-b^2-4b-4[/tex]

We know by identity that , [tex]p^2-q^2 = (p-q)(p+q)[/tex]

⇒  [tex](a-b)(a+b)-4b-4[/tex]

Taking common term out as -4 :

⇒  [tex](a-b)(a+b)-4(b+1)[/tex]

Therefore  , [tex]a^2-b^2-4b-4[/tex] in form of multiplication is  [tex](a-b)(a+b)-4(b+1)[/tex] .

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