Question

Richard and Teo have a combined age of 46. Richard is 13 years older than twice Teo's age. How old are Richard and Teo?

Answer 1

Given that Richard and Teo have a combined age of 46.

Richard is 13 years older than twice Teo's age.

We need to determine the age of Richard and Teo.

Equation:

Let x denote Richard's age.

Let y denote Teo's age.

Let us write the ages in the form of equation.

Thus, we have;

$x+y=46$ and

$x=13+2y$

Solving the equations:

The ages of Richard and Teo can be determined by solving the two equations using substitution method.

Hence, substituting $x=13+2y$ in the equation $x+y=46$, we get;

$13+2y+y=46$

      $13+3y=46$

              $3y=33$

                $y=11$

Thus, the value of y is 11.

Now, substituting $y=11$ in the equation $x+y=46$, we get;

$x+11=46$

       $x=35$

Thus, the value of x is 35.

Age of Richard and Teo:

Thus, the values of x and y are 35 and 11 respectively.

Since, x denote Richard's age and y denote Teo's age, substituting the values, we have;

The age of Richard is 35 years old and the age of Teo is 11 years old.