Respuesta :

The given expression is [tex]\cos \left(2 \cos ^{-1} x\right)[/tex]

We need to determine the expression as an equivalent algebraic expression involving only x.

The expression [tex]\cos \left(2 \cos ^{-1} x\right)[/tex] has to be expressed as an algebraic expression in x.

Thus, we have;

[tex]\cos \left(2 \cos ^{-1} x\right)[/tex]

Using the identity [tex]cos \ (2x)=2cos^2x-1[/tex] in the above expression, we get;

[tex]\cos \left(2 \cos ^{-1} x\right)=2\ cos^2(cos^{-1}x)-1[/tex]

Simplifying, we get;

[tex]\cos \left(2 \cos ^{-1} x\right)=2[cos(cos^{-1}x)]^2-1[/tex]

[tex]\cos \left(2 \cos ^{-1} x\right)=2(x)^2-1[/tex]

[tex]\cos \left(2 \cos ^{-1} x\right)=2x^2-1[/tex]

Hence, the expression [tex]\cos \left(2 \cos ^{-1} x\right)[/tex] can be written as [tex]2x^2-1[/tex]

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