Check out this cube:
Find the surface area of the cube (above) using its net (below).

The surface area of a cube with side of length 3 units is 54 sq. units.
Suppose that the cube in consideration has its side of 'a' units length.
Then, the surface area S of that cube is:
[tex]S = 6(a^2) \: \rm unit^2[/tex]
For this case, the considered cube has side of length 3 units.
Thus, we get its surface area as;
[tex]S = 6(a^2) = 6(3^2) = 6 \times 3\times 3 = 54 \: \rm unit^2[/tex]
Thus, the surface area of a cube with side of length 3 units is 54 sq. units.
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