Question

Problem PageQuestion Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.6 g of butane is mixed with 7.65 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

Answer 1

Answer:

6.47 grams is the maximum mass of carbon dioxide that could be produced by the chemical reaction.

Explanation:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

Moles of butane = $\frac{4.6 g}{58 g/mol}=0.07931 mol$

Moles of oxygen gas = $\frac{7.65 g}{32 g/mol}=0.239 mol$

According to reaction , 13 moles of oxygen gas reacts with 2 moles of butane,then 0.239 moles of oxygen gas will react with :

$\frac{2}{13}\times 0.239 mol=0.0368 mol$ of butane.

From this we can see that butane is present in an excess amount and oxygen gas is present in limited amount. Hence, oxygen gas is a limiting reagent.

Since, oxygen gas is a limiting reagent which means that amount of carbon dioxide gas produce will depend upon moles of oxygen gas.

According to reaction, 13 moles of oxygen gas gives 8 moles of carbon dioxide, then 0.239 moles of oxygen gas will give:

$\frac{8}{13}\times 0.239 mol=0.147 mol$

Mass of 0.1471 moles of carbon dioxide gas:

0.147 mol × 44.01 g/mol = 6.47 g

6.47 grams is the maximum mass of carbon dioxide that could be produced by the chemical reaction.