Answer:
Step-by-step explanation:
Hello!
X: the amount of money saved by making an online doctor visit.
Assuming that the population has a normal distribution (approx), you have to estimate the mean savings.
n= 20
X[bar]= 70.75
S= 22.57
Using the student t distribution the formula for the interval is:
[X[bar]±[tex]t_{n-1;1-\alpha /2}[/tex]* [tex]\frac{S}{\sqrt{n} }[/tex]]
[tex]t_{n-1;1-\alpha /2}= t_{19;0.975}= 2.093[/tex]
[70.75±2.093*[tex]\frac{22.57}{\sqrt{20} }[/tex]]
[60.19;81.31]
With a confidence level of 95%, you'd expect that the interval [60.19;81.31] will include the population mean of the money saved by doing tele-visits instead of office visits to the doctor.
I hope you have a SUPER day!