Respuesta :
Answer:
No, the manufacturer’s claim doesn't appear to be true, at the 0.05 level of significance.
Step-by-step explanation:
We are given that a manufacturer of submersible pumps claims that at most 30% of the pumps require repairs within the first 5 years of operations. A random sample of 120 of these pumps included 47 which required repairs within the first 5 years.
We have to test the manufacturer’s claim.
Firstly, as we know that the testing is done always on the population parameter.
Let p = % of the pumps that require repairs within the first 5 years of operations.
SO, Null Hypothesis, [tex]H_0[/tex] : [tex]p \leq[/tex] 30% {means that at most 30% of the pumps require repairs within the first 5 years of operations}
Alternate Hypothesis, [tex]H_a[/tex] : p > 30% {means that more than 30% of the pumps require repairs within the first 5 years of operations}
The test statistics that will be used here is One-sample z proportion test;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = proportion of the pumps that require repairs within the first 5 years of operations in a sample of 120 = [tex]\frac{47}{120}[/tex]
n = sample of pumps 120
So, test statistics = [tex]\frac{\frac{47}{120} -0.30}{\sqrt{\frac{\frac{47}{120}(1-\frac{47}{120})}{120} } }[/tex]
= 2.057
Now, at 0.05 level of significance, the z table gives critical value of 1.6449. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that more than 30% of the pumps require repairs within the first 5 years of operations which means the manufacturer’s claim was not true.