Answer:
[tex]1\frac{7}{8}[/tex]
Step-by-step explanation:
Given:
A mixture of green paint requires 3/4 pint yellow paint and 2/5 pint blue paint.
Question asked:
How many pints of yellow paint will be needed if the mixture contains one pint of blue paint ?
Solution:
We will easily find quantity of yellow paint, will be needed in the mixture, contains one pint of blue paint by using unitary method:
By using [tex]\frac{2}{5} \ pint[/tex] blue paint, yellow paint requires = [tex]\frac{3}{4} \ pint[/tex]
By using 1 pint blue paint, yellow paint requires = [tex]\frac{3}{4} \div\frac{2}{5} \\[/tex]
[tex]=\frac{3}{4} \times\frac{5}{2} \\\\ =\frac{15}{8} \\\\ =1\frac{7}{8} \ pint[/tex]
Thus, [tex]1\frac{7}{8}[/tex] pint yellow paint requires in the mixture with one pint of blue paint.