Answer:
The value of x-y is 18
Step-by-step explanation:
From the question, we can deduced the following ;
xy = 144....eqn(1)
x+y=30.......eqn(2)
For eqn(2), we subtract y from both sides to make x the subject.
[tex] \implies x + y - y= 30 - y[/tex]
[tex]\implies x= 30 - y[/tex]
Putting that x=30-y into eqn(1) we obtain;
[tex]y(30 - y)=144[/tex]
[tex]\implies 30y - {y}^{2} =144[/tex]
[tex]\implies 0= {y}^{2} - 30 + 144[/tex]
[tex]\implies 0= {y}^{2} - 24y - 6y+ 144[/tex]
[tex]\implies 0=y(y- 24)- 6(y - 24)[/tex]
[tex]\implies 0=(y- 6)(y - 24)[/tex]
This implies that
y-6=0 or y-24=0
Hence, y=6 or y=24.
Therefore, when x=6 then y=24 and when x=24, then y=6 all satisfy the given equations.
But from the question, x>y.
This implies that,x=24 and y= 6
Thus, the value of x-y=24-6=18