Answer:
2.14344%
Step-by-step explanation:
There are two possible outcomes here, the visitor looking for the websites (p=0.95) and the visitor looking for other websites(q=5%= 0.05). The question asking for the probability of exactly 3 visitors actually looking for the website(X=3) out of 5 visitors (n=5). There is no marking to differentiate the visitors, so the order of the visitors is not important.
The calculation will be:
P(X=x) = nCx ×(p)^x ×(q)^n-x
P(X=3) = 5C3 ×(0.95)^3 ×(0.05)^2
P(X=3) =2.14344%