The electric current passing through the bulb would be 3.3A
Explanation:
Given:
Electric charge, q = 800C
Time, t = 4 min
= 4 X 60 sec
= 240 sec
Electric current, I = ?
We know,
[tex]Current = \frac{Charge}{Time}[/tex]
On substituting the value we get:
[tex]I = \frac{800}{4 X 60} \\\\I = 3.3A[/tex]
Thus, the electric current passing through the bulb would be 3.3A